數(shù)據(jù)庫表間數(shù)據(jù)復(fù)制      在利用數(shù)據(jù)庫開發(fā)時(shí),，常常會(huì)將一些表之間的數(shù)據(jù)互相導(dǎo)入,。當(dāng)然可以編寫程序?qū)崿F(xiàn),，但是,，程序常常需要開發(fā)環(huán)境,，不方便,。最方便是利用sql語言直接導(dǎo)入。既方便而修改也簡單,。以下就是導(dǎo)入的方法,。
1。表結(jié)構(gòu)相同的表,，且在同一數(shù)據(jù)庫（如,，table1,table2)
Sql ：insert into table1 select * from table2 (完全復(fù)制)
insert into table1 select distinct * from table2(不復(fù)制重復(fù)紀(jì)錄）
insert into table1 select top 5 * from table2 (前五條紀(jì)錄)
2。   不在同一數(shù)據(jù)庫中（如,，db1 table1,db2 table2)
sql:    insert into db1..table1 select * from db2..table2 (完全復(fù)制)
insert into db1..table1 select distinct * from db2table2(不復(fù)制重復(fù)紀(jì)錄）
insert into tdb1..able1 select top 5 * from   db2table2 (前五條紀(jì)錄)
3.      表結(jié)構(gòu)不同的表或復(fù)制部分紀(jì)錄（如,，dn_user,dn_user2)
a.    建一個(gè)新表[DN_UserTemp]（在老表dn_user上增加一列)
CREATE TABLE [DN_UserTemp] ( [Num] [numeric](18, 0) IDENTITY (1, 1) NOT NULL）
[Id] [idtype] NOT NULL ,
[Name] [fntype] NOT NULL ,
[Descript] [dstype] NULL ,
[LogonNm] [idtype] NOT NULL ,
[Password] [idtype] NULL ,
[Gender] [char] (1) NULL ,
[Quited] [booltype] NOT NULL,
[OffDuty] [booltype] NOT NULL ,
[Stopped] [booltype] NOT NULL,
[OSBind] [booltype] NOT NULL,
[Domain] [idtype] NULL ,
[EMail] [fntype] NULL ,
[UnitId] [idtype] NULL ,
[BranchId] [idtype] NULL ,
[DutyId] [idtype] NULL ,
[LevelId] [idtype] NULL ,
[ClassId] [idtype] NULL ,
[TypeId] [idtype] NULL ,
[IP] [varchar] (15) COLLATE Chinese_PRC_CI_AS NULL ,
[ExpireDT] [datetime] NULL ,
[Sort] [int] NOT NULL ,
[AllowDel] [booltype] NOT NULL,
[UnitChief] [booltype] NOT NULL,
[BranchChief] [booltype] NOT NULL ,
[UnitDeputy] [booltype] NOT NULL ,
[BranchDeputy] [booltype] NOT NULL ,
[Num] [numeric](18, 0) IDENTITY (1, 1) NOT NULL
) ON [PRIMARY]
b. 將dn_uer2的數(shù)據(jù)拷入dn_usertemp
sql:insert into dn_usertemp select * from dn_user2
c.將dn_usertemp 拷入dn_user
sql:
declare @i int
declare @j int
declare @Name fntype
set @i=1
select @j=count(*) from dn_usertemp
while @i<@j 1
begin
select @Name=Name from dn_usertemp where Num=@i
print @Name
insert into dn_user (Name) values (@Name) where Num=@i
select @i=@i 1
end
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creat到--
然后把數(shù)據(jù)庫名改成想復(fù)制到的那個(gè)庫的名稱