|
|
isset
(PHP 3, PHP 4, PHP 5)
isset -- 檢測變量是否設(shè)置
描述
bool isset ( mixed var [, mixed var [, ...]] )
如果 var 存在則返回 TRUE,,否則返回 FALSE。
如果已經(jīng)使用 unset() 釋放了一個(gè)變量之后,它將不再是 isset(),。若使用 isset() 測試一個(gè)被設(shè)置成 NULL 的變量,,將返回 FALSE,。同時(shí)要注意的是一個(gè) NULL 字節(jié)("\0")并不等同于 PHP 的 NULL 常數(shù),。
警告: isset() 只能用于變量,因?yàn)閭鬟f任何其它參數(shù)都將造成解析錯(cuò)誤,。若想檢測常量是否已設(shè)置,,可使用 defined() 函數(shù)。
這對于數(shù)組中的元素也同樣有效:
注: 由于這是一個(gè)語言結(jié)構(gòu)而非函數(shù),因此它無法被變量函數(shù)調(diào)用,。
參見 empty(),、unset()、defined(),、array_key_exists() 和錯(cuò)誤控制 @ 運(yùn)算符,。
soywiz at php dot net14-Apr-2006 09:12
Sometimes you have to check if an array has some keys. To achieve it you can use "isset" like this: isset($array['key1'], $array['key2'], $array['key3'], $array['key4']) You have to write $array all times and it is reiterative if you use same array each time.
With this simple function you can check if an array has some keys:
<?php function isset_array() { if (func_num_args() < 2) return true; $args = func_get_args(); $array = array_shift($args); if (!is_array($array)) return false; foreach ($args as $n) if (!isset($array[$n])) return false; return true; } ?>
Use: isset_array($array, 'key1', 'key2', 'key3', 'key4') First parameter has the array; following parameters has the keys you want to check.
kariedoo10-Mar-2006 02:27
Before:
//ask, if is set $number = isset($_GET['number']) ? $_GET['number'] : ''; $age = isset($_GET['age']) ? $_GET['age'] : ''; $street = isset($_GET['street']) ? $_GET['street'] : '';
After: --> it's easier to read
//ask, if is set $parameter = array('number', 'age', 'street'); foreach($parameter as $name) { $$name = isset($_GET[$name]) ? $_GET[$name] : ''; }
red at iklanumum dot com10-Feb-2006 02:02
This could be viewed as a philosophy. I wonder why a NULL variabel is being considered FALSE rather than TRUE while in isset, because if the variable has been unset it becomes undefined but a NULL variabel is still defined although it has no value. Or, perhaps, it's based on the memory usage, if it is how about $x="" ? Is empty value use memory too? This leads me to another thinking that the isset isn't have family relationship with unset although both of it are a language construct and have 'set' word :)
Slawek Petrykowski29-Nov-2005 07:06
<?php $foo = 'a little string'; echo isset($foo)?'yes ':'no ', isset($foo['aaaa'])?'yes ':'no '; >
results with unexpected values: yes yes
Well, it is necessary to check type of $foo first !
Peter Beckman <beckman at purplecow dot com>21-Sep-2005 03:16
Based on the previous post, I've found this code even more useful:
<?php function isset_sum(&$var, $val) { if (isset($var)) $var += $val; else $var = $val; } ?>
Now instead of:
<?php if (isset($foo[$bar][$baz][$fooz])) $foo[$bar][$baz][$fooz] += $count; else $foo[$bar][$baz][$fooz] = $count; ?>
No more "Undefined variable" warnings, and you save your fingers and sanity! Thanks to the previous poster for inspiration.
14-Sep-2005 06:41
I don't know if you guys can use this but i find this piece of code pretty useful (for readabillity at least):
function isset_else( $&v, $r ) { if( isset( $v )) return $v; else return $r; }
This way you can go:
$a = 4;
$c += isset_else( $a, 0 ); $c += isset_else( $b, 0 );
echo $c;
Of course, this code would work anyway, but you get the point.
onno at itmaze dot com dot au ##php==owh12-Aug-2005 03:33
In PHP4, the following works as expected:
if (isset($obj->thing['key'])) { unset($obj->thing['key']) ; }
In PHP5 however you will get a fatal error for the unset().
The work around is:
if (is_array($obj->thing) && isset($obj->thing['key'])) { unset($obj->thing['key']) ; }
richard william lee AT gmail11-Jun-2005 02:38
Just a note on the previous users comments. isset() should only be used for testing if the variable exists and not if the variable containes an empty "" string. empty() is designed for that.
Also, as noted previosuly !empty() is the best method for testing for set non-empty variables.
darkstar_ae at hotmail dot com25-May-2005 04:03
isset doesn't reliably evaluate variables with blank strings (not necessarily NULL). i.e. $blankvar = ""; // isset will return true on this.
This is a very common pitfall when handling HTML forms that return blank text fields to the script. You're better off doing this:
if ($var != "") return true; else return false;
This more of a programming practice rather than the function's shortcomings. So if you have a habit of initializing variables you're likely to run into problems with isset() if your code or php project become very large.
Andrew Penry11-May-2005 11:17
The following is an example of how to test if a variable is set, whether or not it is NULL. It makes use of the fact that an unset variable will throw an E_NOTICE error, but one initialized as NULL will not.
<?php
function var_exists($var){ if (empty($GLOBALS['var_exists_err'])) { return true; } else { unset($GLOBALS['var_exists_err']); return false; } }
function var_existsHandler($errno, $errstr, $errfile, $errline) { $GLOBALS['var_exists_err'] = true; }
$l = NULL; set_error_handler("var_existsHandler", E_NOTICE); echo (var_exists($l)) ? "True " : "False "; echo (var_exists($k)) ? "True " : "False "; restore_error_handler();
?>
Outputs: True False
The problem is, the set_error_handler and restore_error_handler calls can not be inside the function, which means you need 2 extra lines of code every time you are testing. And if you have any E_NOTICE errors caused by other code between the set_error_handler and restore_error_handler they will not be dealt with properly. One solution:
<?php
function var_exists($var){ if (empty($GLOBALS['var_exists_err'])) { return true; } else { unset($GLOBALS['var_exists_err']); return false; } }
function var_existsHandler($errno, $errstr, $errfile, $errline) { $filearr = file($errfile); if (strpos($filearr[$errline-1], 'var_exists') !== false) { $GLOBALS['var_exists_err'] = true; return true; } else { return false; } }
$l = NULL; set_error_handler("var_existsHandler", E_NOTICE); echo (var_exists($l)) ? "True " : "False "; echo (var_exists($k)) ? "True " : "False "; is_null($j); restore_error_handler();
?>
Outputs: True False Notice: Undefined variable: j in filename.php on line 26
This will make the handler only handle var_exists, but it adds a lot of overhead. Everytime an E_NOTICE error happens, the file it originated from will be loaded into an array.
phpnet dot 5 dot reinhold2000 at t spamgourmet dot com10-Apr-2005 11:33
if you want to check whether the user has sent post vars from a form, it is a pain to write something like the following, since isset() does not check for zero-length strings:
if(isset($form_name) && $form_name != '') [...]
a shorter way would be this one:
if($form_name && $form_message) [...]
but this is dirty since you cannot make sure these variables exist and php will echo a warning if you refer to a non-existing variable like this. plus, a string containing "0" will evaluate to FALSE if casted to a boolean.
this function will check one or more form values if they are set and do not contain an empty string. it returns false on the first empty or non-existing post var.
<? function postvars() { foreach(func_get_args() as $var) { if(!isset($_POST[$var]) || $_POST[$var] === '') return false; } return true; } ?>
example: if(postvars('form_name','form_message')) [...]
yaogzhan at gmail dot com20-Mar-2005 08:52
in PHP5, if you have
<?PHP class Foo { protected $data = array('bar' => null);
function __get($p) { if( isset($this->data[$p]) ) return $this->data[$p]; } } ?>
and <?PHP $foo = new Foo; echo isset($foo->bar); ?> will always echo 'false'. because the isset() accepts VARIABLES as it parameters, but in this case, $foo->bar is NOT a VARIABLE. it is a VALUE returned from the __get() method of the class Foo. thus the isset($foo->bar) expreesion will always equal 'false'.
dubmeier aaattt Y! daht calm02-Mar-2005 07:13
Here are some handy wrappers to isset that I use when I need to do common evaluations like: this variable is set and has a length greater than 0, or: I want the variables value, or a blank, if not set.
/** * isset_echo() * * Accomplishes the following w/o warnings: * echo $x; * echo $x[$y]; * echo $x[$y][$z]; * * FIXME: make this recursive so it works for N args? */ function isset_echo($x, $y=Null, $z=Null) { if (is_array($x)) { if (array_key_exists($y, $x)) { if (is_array($x[$y])) { if (array_key_exists($z, $x[$y])) { echo $x[$y][$z]; } } else { echo $x[$y]; } } } else { echo $x; } }
/** * isset_value() * * As above, but returns value instead of echoing */ function isset_value(&$x, $y=Null) { if (is_array($x)) { if (array_key_exists($y, $x)) { return $x[$y]; } } else { return $x; } }
/** * isset_and_equals() * * As above, but ... * Returns true if variable (or array member) is set and equaL to the first parameter */ function isset_equals($val, $w, $x=null, $y=null, $z=null) { if (is_array($w)) { if (array_key_exists($x, $w)) { if (is_array($w[$x])) { if (array_key_exists($y, $w[$x])) { if (is_array($w[$x][$y])) { if(array_key_exists($z, $w[$x][$y])) { return ($w[$x][$y][$z] == $val) ? true : false; } } else { return ($w[$x][$y] == $val) ? true : false; } } } else { return ($w[$x] == $val) ? true : false; } } } else { return ($w == $val) ? true : false; } }
/** * isset_gt0() * * As above, but returns true only if var is set and it's length is > 0 */ function isset_gt0(&$x) { if (isset($x) && strlen($x) > 0) { return true; } else { return false; } }
codeslinger at compsalot dot com07-Feb-2005 02:21
according to the docs -- "isset() will return FALSE if testing a variable that has been set to NULL."
That statment is not always correct, sometimes isset() returns TRUE for a NULL value. But the scenarios are obtuse. There are a tons of bugs on this subject, all marked as bogus.
Problems occur when NULLs are in named fields of arrays and also when vars are passed by reference.
do lots of testing and code defensively.
is_null() is your friend...
pianistsk8er at gmail dot com10-Dec-2004 10:23
This function is very useful while calling to the URL to specify which template to be used on certain parts of your application.
Here is an example...
<?php
$cat = $_GET['c']; $id = $_GET['id']; $error = 'templates/error.tpl';
if( isset($cat)) { if( isset($id)) { $var = 'templates/pics/' . $cat . '-' . $id . '.tpl'; if (is_file($var)) { include($var); } else { include($error); } } else { $var = 'templates/pics/' . $cat . '.tpl'; if (is_file($var)) { include($var); } else { include($error); } } } else { include('templates/alternative.'.tpl); }
?>
You can see several uses of the isset function being used to specify wheter a template is to be called upon or not. This can easily prevent other generic PHP errors.
jc dot michel at symetrie dot com15-Nov-2004 06:35
Using isset($array['key']) is useful, but be careful! using isset($array['key']['subkey']) doesn't work as one could expect, if $array['key'] is a string it seems that 'subkey' is converted to (integer) 0 and $array['key']['subkey'] is evaluated as the first char of the string. The solution is to use is_array($array['key']) && isset($array['key']['subkey'])
Here is a small code to show this:
<?php $ex = array('one' => 'val1','two' => 'val2'); echo '$ex = ';print_r($ex); echo "<br />";
echo " isset(\$ex['one']['three']) : "; if (isset($ex['one']['three'])) echo 'true'; else echo 'false';
echo "<br />"; echo "is_array(\$ex['one']) && isset(\$ex['one']['three']) : "; if (is_array($ex['one']) && isset($ex['one']['three'])) echo 'true'; else echo 'false'; ?>
shows: $ex = Array ( [one] => val1 [two] => val2 ) isset($ex['one']['three']) : true is_array($ex['one']) && isset($ex['one']['three']) : false
jon08-Dec-2003 02:19
Since PHP will check cases in order, I often end up using this bit of code:
<?php if (isset($var) && $var) { // do something } ?>
In short, if you have error reporting on, and $var is not set, PHP will generate an error if you just have:
<?php if ($var) { // do something } ?>
...but, as noted elsewhere, will return True if set to False in this case: <?php if (isset($var)) { // do something } ?>
Checking both to see if $var is set, and that it equals something other than Null or False is something I find very useful a lot of times. If $var is not set, PHP will never execute the second part of "(isset($var) && $var)", and thus never generate an error either.
This also works very nice for setting variable as well, e.g.: <?php $var = (isset($var) && $var) ? $var : 'new value'; ?>
flobee at gmx dot net09-Sep-2003 05:16
just as note: if you want to check variables by boolean value: true or false , "isset" has a different meaning! <?php $var=null; // sample 1 if($var) { // if true or another value exept "false" , "null": go on here echo "1. var is true or has a value $var<br>"; } else { echo "1. var is "false" or "null"<br>"; }
if(!$var) { // if false or "null": go on here echo "2. var has no value $var<br>"; } else { echo "2. var is "false" or "null"<br>"; }
// sample 2 $var =false; if(isset($var)) { // $var is false so it is set to a value and the execution goes here echo "3. var has value: $var<br>"; }
$var=null; if(!isset($var)) { // $var is null (does not exist at this time) and the execution goes here echo "4. var was not set $var<br>"; } ?>
|
|
|
|